5/(b – 3) + 1/(b + 3) - 6/(9 - b^2) = 5/(b – 3) + 1/(b + 3) + 6/(b^2 – 9). Приведем дроби к общему знаменателю (b^2 - 9). (5 * (b + 3)) + 1 * (b - 3) + 6)/(b^2 – 9) = (5 * b + 15 + b – 3 + 6)/(b^2 – 9) = (6 * b + 18)/(b^2 – 9) = 6 * (b + 3)/(b – 3) * (b + 3) = 6/(b – 3). 6/(16/7 – 3) = 6/(17/7 – 21/7) = 6/(-4/7) = -42/4 = -10,5. Ответ: -10,5.